2(x+3)=162(x+3)=16

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Solution for 2(x+3)=162(x+3)=16 equation: 



2(x+3)=162(x+3)=16

We move all terms to the left:

2(x+3)-(162(x+3))=0

We multiply parentheses

2x-(162(x+3))+6=0



We calculate terms in parentheses: -(162(x+3)), so:

162(x+3)

We multiply parentheses

162x+486

Back to the equation:

-(162x+486)



We get rid of parentheses

2x-162x-486+6=0

We add all the numbers together, and all the variables

-160x-480=0

We move all terms containing x to the left, all other terms to the right

-160x=480

x=480/-160

x=-3

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