2(x+3)=18-4(x+2)

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Solution for 2(x+3)=18-4(x+2) equation: 



2(x+3)=18-4(x+2)

We move all terms to the left:

2(x+3)-(18-4(x+2))=0

We multiply parentheses

2x-(18-4(x+2))+6=0



We calculate terms in parentheses: -(18-4(x+2)), so:

18-4(x+2)

determiningTheFunctionDomain
-4(x+2)+18

We multiply parentheses

-4x-8+18

We add all the numbers together, and all the variables

-4x+10

Back to the equation:

-(-4x+10)



We get rid of parentheses

2x+4x-10+6=0

We add all the numbers together, and all the variables

6x-4=0

We move all terms containing x to the left, all other terms to the right

6x=4

x=4/6

x=2/3

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