2(x+3)=3(x+1/4)

Solution for 2(x+3)=3(x+1/4) equation:

2(x+3)=3(x+1/4)

We move all terms to the left:

2(x+3)-(3(x+1/4))=0

We add all the numbers together, and all the variables

2(x+3)-(3(+x+1/4))=0

We multiply parentheses

2x-(3(+x+1/4))+6=0

We multiply all the terms by the denominator


2x*4))-(3(+x+1+6*4))=0

We add all the numbers together, and all the variables

2x*4))-(3(x+25))=0

We add all the numbers together, and all the variables

2x*4))-(3(x=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$