2(x+3)=4(2x-8)+2x-2

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Solution for 2(x+3)=4(2x-8)+2x-2 equation:



2(x+3)=4(2x-8)+2x-2
We move all terms to the left:
2(x+3)-(4(2x-8)+2x-2)=0
We multiply parentheses
2x-(4(2x-8)+2x-2)+6=0
We calculate terms in parentheses: -(4(2x-8)+2x-2), so:
4(2x-8)+2x-2
We add all the numbers together, and all the variables
2x+4(2x-8)-2
We multiply parentheses
2x+8x-32-2
We add all the numbers together, and all the variables
10x-34
Back to the equation:
-(10x-34)
We get rid of parentheses
2x-10x+34+6=0
We add all the numbers together, and all the variables
-8x+40=0
We move all terms containing x to the left, all other terms to the right
-8x=-40
x=-40/-8
x=+5

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