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2(x+3)=5(2x-5)
We move all terms to the left:
2(x+3)-(5(2x-5))=0
We multiply parentheses
2x-(5(2x-5))+6=0
We calculate terms in parentheses: -(5(2x-5)), so:We get rid of parentheses
5(2x-5)
We multiply parentheses
10x-25
Back to the equation:
-(10x-25)
2x-10x+25+6=0
We add all the numbers together, and all the variables
-8x+31=0
We move all terms containing x to the left, all other terms to the right
-8x=-31
x=-31/-8
x=3+7/8
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