2(x+3)=5(x-4)+8

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Solution for 2(x+3)=5(x-4)+8 equation: 



2(x+3)=5(x-4)+8

We move all terms to the left:

2(x+3)-(5(x-4)+8)=0

We multiply parentheses

2x-(5(x-4)+8)+6=0



We calculate terms in parentheses: -(5(x-4)+8), so:

5(x-4)+8

We multiply parentheses

5x-20+8

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We get rid of parentheses

2x-5x+12+6=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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