2(x+3)=6(x+3)-8

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Solution for 2(x+3)=6(x+3)-8 equation: 



2(x+3)=6(x+3)-8

We move all terms to the left:

2(x+3)-(6(x+3)-8)=0

We multiply parentheses

2x-(6(x+3)-8)+6=0



We calculate terms in parentheses: -(6(x+3)-8), so:

6(x+3)-8

We multiply parentheses

6x+18-8

We add all the numbers together, and all the variables

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

2x-6x-10+6=0

We add all the numbers together, and all the variables

-4x-4=0

We move all terms containing x to the left, all other terms to the right

-4x=4

x=4/-4

x=-1

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