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2(x+3)=7(x-1)-22
We move all terms to the left:
2(x+3)-(7(x-1)-22)=0
We multiply parentheses
2x-(7(x-1)-22)+6=0
We calculate terms in parentheses: -(7(x-1)-22), so:We get rid of parentheses
7(x-1)-22
We multiply parentheses
7x-7-22
We add all the numbers together, and all the variables
7x-29
Back to the equation:
-(7x-29)
2x-7x+29+6=0
We add all the numbers together, and all the variables
-5x+35=0
We move all terms containing x to the left, all other terms to the right
-5x=-35
x=-35/-5
x=+7
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