2(x+3)=7(x-3)-8

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Solution for 2(x+3)=7(x-3)-8 equation: 



2(x+3)=7(x-3)-8

We move all terms to the left:

2(x+3)-(7(x-3)-8)=0

We multiply parentheses

2x-(7(x-3)-8)+6=0



We calculate terms in parentheses: -(7(x-3)-8), so:

7(x-3)-8

We multiply parentheses

7x-21-8

We add all the numbers together, and all the variables

7x-29

Back to the equation:

-(7x-29)



We get rid of parentheses

2x-7x+29+6=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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