2(x+3)=8(x-2)-8

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Solution for 2(x+3)=8(x-2)-8 equation: 



2(x+3)=8(x-2)-8

We move all terms to the left:

2(x+3)-(8(x-2)-8)=0

We multiply parentheses

2x-(8(x-2)-8)+6=0



We calculate terms in parentheses: -(8(x-2)-8), so:

8(x-2)-8

We multiply parentheses

8x-16-8

We add all the numbers together, and all the variables

8x-24

Back to the equation:

-(8x-24)



We get rid of parentheses

2x-8x+24+6=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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