2(x+3)=8-(x+6)

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Solution for 2(x+3)=8-(x+6) equation: 



2(x+3)=8-(x+6)

We move all terms to the left:

2(x+3)-(8-(x+6))=0

We multiply parentheses

2x-(8-(x+6))+6=0



We calculate terms in parentheses: -(8-(x+6)), so:

8-(x+6)

determiningTheFunctionDomain
-(x+6)+8

We get rid of parentheses

-x-6+8

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We get rid of parentheses

2x+1x-2+6=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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