2(x+3)=8-2(2x-5)

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Solution for 2(x+3)=8-2(2x-5) equation: 



2(x+3)=8-2(2x-5)

We move all terms to the left:

2(x+3)-(8-2(2x-5))=0

We multiply parentheses

2x-(8-2(2x-5))+6=0



We calculate terms in parentheses: -(8-2(2x-5)), so:

8-2(2x-5)

determiningTheFunctionDomain
-2(2x-5)+8

We multiply parentheses

-4x+10+8

We add all the numbers together, and all the variables

-4x+18

Back to the equation:

-(-4x+18)



We get rid of parentheses

2x+4x-18+6=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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