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2(x+3)=9(x-5)-16
We move all terms to the left:
2(x+3)-(9(x-5)-16)=0
We multiply parentheses
2x-(9(x-5)-16)+6=0
We calculate terms in parentheses: -(9(x-5)-16), so:We get rid of parentheses
9(x-5)-16
We multiply parentheses
9x-45-16
We add all the numbers together, and all the variables
9x-61
Back to the equation:
-(9x-61)
2x-9x+61+6=0
We add all the numbers together, and all the variables
-7x+67=0
We move all terms containing x to the left, all other terms to the right
-7x=-67
x=-67/-7
x=9+4/7
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