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2(x+30)+5x=3(2x-1)
We move all terms to the left:
2(x+30)+5x-(3(2x-1))=0
We add all the numbers together, and all the variables
5x+2(x+30)-(3(2x-1))=0
We multiply parentheses
5x+2x-(3(2x-1))+60=0
We calculate terms in parentheses: -(3(2x-1)), so:We add all the numbers together, and all the variables
3(2x-1)
We multiply parentheses
6x-3
Back to the equation:
-(6x-3)
7x-(6x-3)+60=0
We get rid of parentheses
7x-6x+3+60=0
We add all the numbers together, and all the variables
x+63=0
We move all terms containing x to the left, all other terms to the right
x=-63
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