2(x+4)(x-2)/3(x2-4x+4)

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Solution for 2(x+4)(x-2)/3(x2-4x+4) equation: 


x in (-oo:+oo)

((2*(x+4)*(x-2))/3)*(x^2-(4*x)+4) = 0

((2*(x+4)*(x-2))/3)*(x^2-4*x+4) = 0

(2*(x+4)*(x-2)*(x^2-4*x+4))/3 = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

(x-2)^2 = 0

(2*(x+4)*(x-2)^3)/3 = 0

( x+4 )

x+4 = 0 // - 4

x = -4

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -4, 2, 2, 2 }

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