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2(x+4)+1=4x-2(-3+x)
We move all terms to the left:
2(x+4)+1-(4x-2(-3+x))=0
We add all the numbers together, and all the variables
2(x+4)-(4x-2(x-3))+1=0
We multiply parentheses
2x-(4x-2(x-3))+8+1=0
We calculate terms in parentheses: -(4x-2(x-3)), so:We add all the numbers together, and all the variables
4x-2(x-3)
We multiply parentheses
4x-2x+6
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
2x-(2x+6)+9=0
We get rid of parentheses
2x-2x-6+9=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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