2(x+4)+2(x-2)=X+3+x+4+x+5

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Solution for 2(x+4)+2(x-2)=X+3+x+4+x+5 equation: 



2(x+4)+2(x-2)=x+3+x+4+x+5

We move all terms to the left:

2(x+4)+2(x-2)-(x+3+x+4+x+5)=0

We add all the numbers together, and all the variables

2(x+4)+2(x-2)-(3x+12)=0

We multiply parentheses

2x+2x-(3x+12)+8-4=0

We get rid of parentheses

2x+2x-3x-12+8-4=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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