2(x+4)+3(x+1)=41

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Solution for 2(x+4)+3(x+1)=41 equation: 



2(x+4)+3(x+1)=41

We move all terms to the left:

2(x+4)+3(x+1)-(41)=0

We multiply parentheses

2x+3x+8+3-41=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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