2(x+4)+3x-7=7x+12-x

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Solution for 2(x+4)+3x-7=7x+12-x equation: 



2(x+4)+3x-7=7x+12-x

We move all terms to the left:

2(x+4)+3x-7-(7x+12-x)=0

We add all the numbers together, and all the variables

2(x+4)+3x-(6x+12)-7=0

We add all the numbers together, and all the variables

3x+2(x+4)-(6x+12)-7=0

We multiply parentheses

3x+2x-(6x+12)+8-7=0

We get rid of parentheses

3x+2x-6x-12+8-7=0

We add all the numbers together, and all the variables

-1x-11=0

We move all terms containing x to the left, all other terms to the right

-x=11

x=11/-1

x=-11

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