2(x+4)+3x=8+3(x-4)

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Solution for 2(x+4)+3x=8+3(x-4) equation:



2(x+4)+3x=8+3(x-4)
We move all terms to the left:
2(x+4)+3x-(8+3(x-4))=0
We add all the numbers together, and all the variables
3x+2(x+4)-(8+3(x-4))=0
We multiply parentheses
3x+2x-(8+3(x-4))+8=0
We calculate terms in parentheses: -(8+3(x-4)), so:
8+3(x-4)
determiningTheFunctionDomain 3(x-4)+8
We multiply parentheses
3x-12+8
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
We add all the numbers together, and all the variables
5x-(3x-4)+8=0
We get rid of parentheses
5x-3x+4+8=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6

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