2(x+4)+4x-6=6(8+2x)-6

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Solution for 2(x+4)+4x-6=6(8+2x)-6 equation: 



2(x+4)+4x-6=6(8+2x)-6

We move all terms to the left:

2(x+4)+4x-6-(6(8+2x)-6)=0

We add all the numbers together, and all the variables

2(x+4)+4x-(6(2x+8)-6)-6=0

We add all the numbers together, and all the variables

4x+2(x+4)-(6(2x+8)-6)-6=0

We multiply parentheses

4x+2x-(6(2x+8)-6)+8-6=0



We calculate terms in parentheses: -(6(2x+8)-6), so:

6(2x+8)-6

We multiply parentheses

12x+48-6

We add all the numbers together, and all the variables

12x+42

Back to the equation:

-(12x+42)



We add all the numbers together, and all the variables

6x-(12x+42)+2=0

We get rid of parentheses

6x-12x-42+2=0

We add all the numbers together, and all the variables

-6x-40=0

We move all terms containing x to the left, all other terms to the right

-6x=40

x=40/-6

x=-6+2/3

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