2(x+4)+4x=4(x+2)+8

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Solution for 2(x+4)+4x=4(x+2)+8 equation: 



2(x+4)+4x=4(x+2)+8

We move all terms to the left:

2(x+4)+4x-(4(x+2)+8)=0

We add all the numbers together, and all the variables

4x+2(x+4)-(4(x+2)+8)=0

We multiply parentheses

4x+2x-(4(x+2)+8)+8=0



We calculate terms in parentheses: -(4(x+2)+8), so:

4(x+2)+8

We multiply parentheses

4x+8+8

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

6x-(4x+16)+8=0

We get rid of parentheses

6x-4x-16+8=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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