2(x+4)+4x=4(x+2)+8

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Solution for 2(x+4)+4x=4(x+2)+8 equation:



2(x+4)+4x=4(x+2)+8
We move all terms to the left:
2(x+4)+4x-(4(x+2)+8)=0
We add all the numbers together, and all the variables
4x+2(x+4)-(4(x+2)+8)=0
We multiply parentheses
4x+2x-(4(x+2)+8)+8=0
We calculate terms in parentheses: -(4(x+2)+8), so:
4(x+2)+8
We multiply parentheses
4x+8+8
We add all the numbers together, and all the variables
4x+16
Back to the equation:
-(4x+16)
We add all the numbers together, and all the variables
6x-(4x+16)+8=0
We get rid of parentheses
6x-4x-16+8=0
We add all the numbers together, and all the variables
2x-8=0
We move all terms containing x to the left, all other terms to the right
2x=8
x=8/2
x=4

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