2(x+4)+5=5(x-3)+10

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Solution for 2(x+4)+5=5(x-3)+10 equation: 



2(x+4)+5=5(x-3)+10

We move all terms to the left:

2(x+4)+5-(5(x-3)+10)=0

We multiply parentheses

2x-(5(x-3)+10)+8+5=0



We calculate terms in parentheses: -(5(x-3)+10), so:

5(x-3)+10

We multiply parentheses

5x-15+10

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We add all the numbers together, and all the variables

2x-(5x-5)+13=0

We get rid of parentheses

2x-5x+5+13=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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