2(x+4)+5x(x+4)=0

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Solution for 2(x+4)+5x(x+4)=0 equation:



2(x+4)+5x(x+4)=0
We multiply parentheses
5x^2+2x+20x+8=0
We add all the numbers together, and all the variables
5x^2+22x+8=0
a = 5; b = 22; c = +8;
Δ = b2-4ac
Δ = 222-4·5·8
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-18}{2*5}=\frac{-40}{10} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+18}{2*5}=\frac{-4}{10} =-2/5 $

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