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2(x+4)+6=4x-2(-5+x)
We move all terms to the left:
2(x+4)+6-(4x-2(-5+x))=0
We add all the numbers together, and all the variables
2(x+4)-(4x-2(x-5))+6=0
We multiply parentheses
2x-(4x-2(x-5))+8+6=0
We calculate terms in parentheses: -(4x-2(x-5)), so:We add all the numbers together, and all the variables
4x-2(x-5)
We multiply parentheses
4x-2x+10
We add all the numbers together, and all the variables
2x+10
Back to the equation:
-(2x+10)
2x-(2x+10)+14=0
We get rid of parentheses
2x-2x-10+14=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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