2(x+4)+8(x-2)=12

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Solution for 2(x+4)+8(x-2)=12 equation: 



2(x+4)+8(x-2)=12

We move all terms to the left:

2(x+4)+8(x-2)-(12)=0

We multiply parentheses

2x+8x+8-16-12=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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