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2(x+4)-2=2(x-3)
We move all terms to the left:
2(x+4)-2-(2(x-3))=0
We multiply parentheses
2x-(2(x-3))+8-2=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
2x-(2x-6)+6=0
We get rid of parentheses
2x-2x+6+6=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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