2(x+4)-3=-3(2x-4)+8x

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Solution for 2(x+4)-3=-3(2x-4)+8x equation: 



2(x+4)-3=-3(2x-4)+8x

We move all terms to the left:

2(x+4)-3-(-3(2x-4)+8x)=0

We multiply parentheses

2x-(-3(2x-4)+8x)+8-3=0



We calculate terms in parentheses: -(-3(2x-4)+8x), so:

-3(2x-4)+8x

We add all the numbers together, and all the variables

8x-3(2x-4)

We multiply parentheses

8x-6x+12

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

2x-(2x+12)+5=0

We get rid of parentheses

2x-2x-12+5=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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