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2(x+4)-3=3(x+1)-x+2
We move all terms to the left:
2(x+4)-3-(3(x+1)-x+2)=0
We multiply parentheses
2x-(3(x+1)-x+2)+8-3=0
We calculate terms in parentheses: -(3(x+1)-x+2), so:We add all the numbers together, and all the variables
3(x+1)-x+2
We add all the numbers together, and all the variables
-1x+3(x+1)+2
We multiply parentheses
-1x+3x+3+2
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
2x-(2x+5)+5=0
We get rid of parentheses
2x-2x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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