2(x+4)-3=9-3(x-2)

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Solution for 2(x+4)-3=9-3(x-2) equation: 



2(x+4)-3=9-3(x-2)

We move all terms to the left:

2(x+4)-3-(9-3(x-2))=0

We multiply parentheses

2x-(9-3(x-2))+8-3=0



We calculate terms in parentheses: -(9-3(x-2)), so:

9-3(x-2)

determiningTheFunctionDomain
-3(x-2)+9

We multiply parentheses

-3x+6+9

We add all the numbers together, and all the variables

-3x+15

Back to the equation:

-(-3x+15)



We add all the numbers together, and all the variables

2x-(-3x+15)+5=0

We get rid of parentheses

2x+3x-15+5=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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