2(x+4)/3=7-3(x-3)/6

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Solution for 2(x+4)/3=7-3(x-3)/6 equation: 



2(x+4)/3=7-3(x-3)/6

We move all terms to the left:

2(x+4)/3-(7-3(x-3)/6)=0

We calculate fractions


2x/()+(-(7-3(x-3)*3)/()=0



We calculate terms in parentheses: +(-(7-3(x-3)*3)/(), so:

-(7-3(x-3)*3)/(

We multiply all the terms by the denominator


-(7-3(x-3)*3)



We calculate terms in parentheses: -(7-3(x-3)*3), so:

7-3(x-3)*3

determiningTheFunctionDomain
-3(x-3)*3+7

We multiply parentheses

-9x+27+7

We add all the numbers together, and all the variables

-9x+34

Back to the equation:

-(-9x+34)



We get rid of parentheses

9x-34

Back to the equation:

+(9x-34)



We get rid of parentheses

2x/()+9x-34=0

We multiply all the terms by the denominator


2x+9x*()-34*()=0

We add all the numbers together, and all the variables

2x+9x*()=0

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