2(x+4)1=-3(x+5)

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Solution for 2(x+4)1=-3(x+5) equation: 



2(x+4)1=-3(x+5)

We move all terms to the left:

2(x+4)1-(-3(x+5))=0

We multiply parentheses

2x-(-3(x+5))+8=0



We calculate terms in parentheses: -(-3(x+5)), so:

-3(x+5)

We multiply parentheses

-3x-15

Back to the equation:

-(-3x-15)



We get rid of parentheses

2x+3x+15+8=0

We add all the numbers together, and all the variables

5x+23=0

We move all terms containing x to the left, all other terms to the right

5x=-23

x=-23/5

x=-4+3/5

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