2(x+4)=-3(3x-2)+3x

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Solution for 2(x+4)=-3(3x-2)+3x equation: 



2(x+4)=-3(3x-2)+3x

We move all terms to the left:

2(x+4)-(-3(3x-2)+3x)=0

We multiply parentheses

2x-(-3(3x-2)+3x)+8=0



We calculate terms in parentheses: -(-3(3x-2)+3x), so:

-3(3x-2)+3x

We add all the numbers together, and all the variables

3x-3(3x-2)

We multiply parentheses

3x-9x+6

We add all the numbers together, and all the variables

-6x+6

Back to the equation:

-(-6x+6)



We get rid of parentheses

2x+6x-6+8=0

We add all the numbers together, and all the variables

8x+2=0

We move all terms containing x to the left, all other terms to the right

8x=-2

x=-2/8

x=-1/4

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