2(x+4)=-6(x-4)+8

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Solution for 2(x+4)=-6(x-4)+8 equation: 



2(x+4)=-6(x-4)+8

We move all terms to the left:

2(x+4)-(-6(x-4)+8)=0

We multiply parentheses

2x-(-6(x-4)+8)+8=0



We calculate terms in parentheses: -(-6(x-4)+8), so:

-6(x-4)+8

We multiply parentheses

-6x+24+8

We add all the numbers together, and all the variables

-6x+32

Back to the equation:

-(-6x+32)



We get rid of parentheses

2x+6x-32+8=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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