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2(x+4)=3(3x-4)
We move all terms to the left:
2(x+4)-(3(3x-4))=0
We multiply parentheses
2x-(3(3x-4))+8=0
We calculate terms in parentheses: -(3(3x-4)), so:We get rid of parentheses
3(3x-4)
We multiply parentheses
9x-12
Back to the equation:
-(9x-12)
2x-9x+12+8=0
We add all the numbers together, and all the variables
-7x+20=0
We move all terms containing x to the left, all other terms to the right
-7x=-20
x=-20/-7
x=2+6/7
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