2(x+4)=35-(7-4x)

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Solution for 2(x+4)=35-(7-4x) equation: 



2(x+4)=35-(7-4x)

We move all terms to the left:

2(x+4)-(35-(7-4x))=0

We add all the numbers together, and all the variables

2(x+4)-(35-(-4x+7))=0

We multiply parentheses

2x-(35-(-4x+7))+8=0



We calculate terms in parentheses: -(35-(-4x+7)), so:

35-(-4x+7)

determiningTheFunctionDomain
-(-4x+7)+35

We get rid of parentheses

4x-7+35

We add all the numbers together, and all the variables

4x+28

Back to the equation:

-(4x+28)



We get rid of parentheses

2x-4x-28+8=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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