2(x+4)=42(x-2)-2x

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Solution for 2(x+4)=42(x-2)-2x equation: 



2(x+4)=42(x-2)-2x

We move all terms to the left:

2(x+4)-(42(x-2)-2x)=0

We multiply parentheses

2x-(42(x-2)-2x)+8=0



We calculate terms in parentheses: -(42(x-2)-2x), so:

42(x-2)-2x

We add all the numbers together, and all the variables

-2x+42(x-2)

We multiply parentheses

-2x+42x-84

We add all the numbers together, and all the variables

40x-84

Back to the equation:

-(40x-84)



We get rid of parentheses

2x-40x+84+8=0

We add all the numbers together, and all the variables

-38x+92=0

We move all terms containing x to the left, all other terms to the right

-38x=-92

x=-92/-38

x=2+8/19

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