2(x+4)=7(x-8)-33

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Solution for 2(x+4)=7(x-8)-33 equation: 



2(x+4)=7(x-8)-33

We move all terms to the left:

2(x+4)-(7(x-8)-33)=0

We multiply parentheses

2x-(7(x-8)-33)+8=0



We calculate terms in parentheses: -(7(x-8)-33), so:

7(x-8)-33

We multiply parentheses

7x-56-33

We add all the numbers together, and all the variables

7x-89

Back to the equation:

-(7x-89)



We get rid of parentheses

2x-7x+89+8=0

We add all the numbers together, and all the variables

-5x+97=0

We move all terms containing x to the left, all other terms to the right

-5x=-97

x=-97/-5

x=19+2/5

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