2(x+4)=7+5(x-4)

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Solution for 2(x+4)=7+5(x-4) equation:



2(x+4)=7+5(x-4)
We move all terms to the left:
2(x+4)-(7+5(x-4))=0
We multiply parentheses
2x-(7+5(x-4))+8=0
We calculate terms in parentheses: -(7+5(x-4)), so:
7+5(x-4)
determiningTheFunctionDomain 5(x-4)+7
We multiply parentheses
5x-20+7
We add all the numbers together, and all the variables
5x-13
Back to the equation:
-(5x-13)
We get rid of parentheses
2x-5x+13+8=0
We add all the numbers together, and all the variables
-3x+21=0
We move all terms containing x to the left, all other terms to the right
-3x=-21
x=-21/-3
x=+7

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