2(x+4,3)+3x=-3x(x+1)+3,6

Solution for 2(x+4,3)+3x=-3x(x+1)+3,6 equation:

2(x+4.3)+3x=-3x(x+1)+3.6

We move all terms to the left:

2(x+4.3)+3x-(-3x(x+1)+3.6)=0

We add all the numbers together, and all the variables

3x+2(x+4.3)-(-3x(x+1)+3.6)=0

We multiply parentheses

3x+2x-(-3x(x+1)+3.6)+8.6=0


We calculate terms in parentheses: -(-3x(x+1)+3.6), so:

-3x(x+1)+3.6

We multiply parentheses

-3x^2-3x+3.6

Back to the equation:

-(-3x^2-3x+3.6)


We add all the numbers together, and all the variables

-(-3x^2-3x+3.6)+5x+8.6=0

We get rid of parentheses

3x^2+3x+5x-3.6+8.6=0

We add all the numbers together, and all the variables

3x^2+8x+5=0

a = 3; b = 8; c = +5;
Δ = b2-4ac
Δ = 82-4·3·5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*3}=\frac{-10}{6}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*3}=\frac{-6}{6}
=-1
$