2(x+5)(x-5)=0

Solution for 2(x+5)(x-5)=0 equation:

Simplifying
2(x + 5)(x + -5) = 0

Reorder the terms:
2(5 + x)(x + -5) = 0

Reorder the terms:
2(5 + x)(-5 + x) = 0

Multiply (5 + x) * (-5 + x)
2(5(-5 + x) + x(-5 + x)) = 0
2((-5 * 5 + x * 5) + x(-5 + x)) = 0
2((-25 + 5x) + x(-5 + x)) = 0
2(-25 + 5x + (-5 * x + x * x)) = 0
2(-25 + 5x + (-5x + x2)) = 0

Combine like terms: 5x + -5x = 0
2(-25 + 0 + x2) = 0
2(-25 + x2) = 0
(-25 * 2 + x2 * 2) = 0
(-50 + 2x2) = 0

Solving
-50 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.
-50 + 50 + 2x2 = 0 + 50

Combine like terms: -50 + 50 = 0
0 + 2x2 = 0 + 50
2x2 = 0 + 50

Combine like terms: 0 + 50 = 50
2x2 = 50

Divide each side by '2'.
x2 = 25

Simplifying
x2 = 25

Take the square root of each side:
x = {-5, 5}