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2(x+5)+15=3(4x-1)-2
We move all terms to the left:
2(x+5)+15-(3(4x-1)-2)=0
We multiply parentheses
2x-(3(4x-1)-2)+10+15=0
We calculate terms in parentheses: -(3(4x-1)-2), so:We add all the numbers together, and all the variables
3(4x-1)-2
We multiply parentheses
12x-3-2
We add all the numbers together, and all the variables
12x-5
Back to the equation:
-(12x-5)
2x-(12x-5)+25=0
We get rid of parentheses
2x-12x+5+25=0
We add all the numbers together, and all the variables
-10x+30=0
We move all terms containing x to the left, all other terms to the right
-10x=-30
x=-30/-10
x=+3
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