2(x+5)+3x=3(x+-2)

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Solution for 2(x+5)+3x=3(x+-2) equation: 



2(x+5)+3x=3(x+-2)

We move all terms to the left:

2(x+5)+3x-(3(x+-2))=0

We add all the numbers together, and all the variables

2(x+5)+3x-(3(x-2))=0

We add all the numbers together, and all the variables

3x+2(x+5)-(3(x-2))=0

We multiply parentheses

3x+2x-(3(x-2))+10=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

5x-(3x-6)+10=0

We get rid of parentheses

5x-3x+6+10=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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