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2(x+5)+3x=4(x-3)
We move all terms to the left:
2(x+5)+3x-(4(x-3))=0
We add all the numbers together, and all the variables
3x+2(x+5)-(4(x-3))=0
We multiply parentheses
3x+2x-(4(x-3))+10=0
We calculate terms in parentheses: -(4(x-3)), so:We add all the numbers together, and all the variables
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
5x-(4x-12)+10=0
We get rid of parentheses
5x-4x+12+10=0
We add all the numbers together, and all the variables
x+22=0
We move all terms containing x to the left, all other terms to the right
x=-22
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