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2(x+5)+3x=5(-2x-4)
We move all terms to the left:
2(x+5)+3x-(5(-2x-4))=0
We add all the numbers together, and all the variables
3x+2(x+5)-(5(-2x-4))=0
We multiply parentheses
3x+2x-(5(-2x-4))+10=0
We calculate terms in parentheses: -(5(-2x-4)), so:We add all the numbers together, and all the variables
5(-2x-4)
We multiply parentheses
-10x-20
Back to the equation:
-(-10x-20)
5x-(-10x-20)+10=0
We get rid of parentheses
5x+10x+20+10=0
We add all the numbers together, and all the variables
15x+30=0
We move all terms containing x to the left, all other terms to the right
15x=-30
x=-30/15
x=-2
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