2(x+5)+5(x+2)=10(x-1)

Solution for 2(x+5)+5(x+2)=10(x-1) equation:

2(x+5)+5(x+2)=10(x-1)

We move all terms to the left:

2(x+5)+5(x+2)-(10(x-1))=0

We multiply parentheses

2x+5x-(10(x-1))+10+10=0


We calculate terms in parentheses: -(10(x-1)), so:

10(x-1)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)


We add all the numbers together, and all the variables

7x-(10x-10)+20=0

We get rid of parentheses

7x-10x+10+20=0

We add all the numbers together, and all the variables

-3x+30=0

We move all terms containing x to the left, all other terms to the right

-3x=-30

x=-30/-3

x=+10