2(x+5)-1=(4x-16,20)-3(6-2x)

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Solution for 2(x+5)-1=(4x-16,20)-3(6-2x) equation: 



2(x+5)-1=(4x-16.20)-3(6-2x)

We move all terms to the left:

2(x+5)-1-((4x-16.20)-3(6-2x))=0

We add all the numbers together, and all the variables

2(x+5)-((4x-16.2)-3(-2x+6))-1=0

We multiply parentheses

2x-((4x-16.2)-3(-2x+6))+10-1=0



We calculate terms in parentheses: -((4x-16.2)-3(-2x+6)), so:

(4x-16.2)-3(-2x+6)

We multiply parentheses

(4x-16.2)+6x-18

We get rid of parentheses

4x+6x-16.2-18

We add all the numbers together, and all the variables

10x-34.2

Back to the equation:

-(10x-34.2)



We add all the numbers together, and all the variables

2x-(10x-34.2)+9=0

We get rid of parentheses

2x-10x+34.2+9=0

We add all the numbers together, and all the variables

-8x+43.2=0

We move all terms containing x to the left, all other terms to the right

-8x=-43.2

x=-43.2/-8

x=5+2.6666666666667/6.6666666666667

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