2(x+5)-3(x-2)=4(x-3)

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Solution for 2(x+5)-3(x-2)=4(x-3) equation: 



2(x+5)-3(x-2)=4(x-3)

We move all terms to the left:

2(x+5)-3(x-2)-(4(x-3))=0

We multiply parentheses

2x-3x-(4(x-3))+10+6=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

-1x-(4x-12)+16=0

We get rid of parentheses

-1x-4x+12+16=0

We add all the numbers together, and all the variables

-5x+28=0

We move all terms containing x to the left, all other terms to the right

-5x=-28

x=-28/-5

x=5+3/5

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