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2(x+5)-5(x-2)=32
We move all terms to the left:
2(x+5)-5(x-2)-(32)=0
We multiply parentheses
2x-5x+10+10-32=0
We add all the numbers together, and all the variables
-3x-12=0
We move all terms containing x to the left, all other terms to the right
-3x=12
x=12/-3
x=-4
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