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2(x+5)-6=7(x-3)-6x
We move all terms to the left:
2(x+5)-6-(7(x-3)-6x)=0
We multiply parentheses
2x-(7(x-3)-6x)+10-6=0
We calculate terms in parentheses: -(7(x-3)-6x), so:We add all the numbers together, and all the variables
7(x-3)-6x
We add all the numbers together, and all the variables
-6x+7(x-3)
We multiply parentheses
-6x+7x-21
We add all the numbers together, and all the variables
x-21
Back to the equation:
-(x-21)
2x-(x-21)+4=0
We get rid of parentheses
2x-x+21+4=0
We add all the numbers together, and all the variables
x+25=0
We move all terms containing x to the left, all other terms to the right
x=-25
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